Alabama quarterback Keelon Russell put on a clinic in last Saturday's 50-36 victory over Florida State being named the Shaun Alexander Award Player of the Week, according to a release from the University of Alabama.

 

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In Saturday's victory, Russell completed 23-of-30 pass attempts for 320 yards and three touchdowns through the air, with all three coming in the final nine minutes of the second quarter. He connected on touchdown passes of 21, 46, and 16 yards to three different pass catchers. Russell also showed his dynamic playmaking with his legs, rushing three times for 56 yards and a touchdown.

 

The Shaun Alexander Award is presented to the most outstanding freshman player in college football. Russell appeared in just two games last season for the Crimson Tide, redshirting at season's end. The Crimson Tide's redshirt freshman has led Alabama to a 3-0 start to the 2026 campaign and a climb back into the top 10 of the AP Poll after Alabama started the season at No. 13.

 

No. 8 Alabama will host South Carolina on Saturday, September 26, in Bryant-Denny Stadium. Kickoff is scheduled for 6:00 p.m. on ESPN.

 

Wyatt Fulton is the Tide 100.9 DME and Brand Manager, primarily covering Alabama Crimson Tide football and men's basketball. For more Crimson Tide coverage, follow Wyatt on X (Formerly known as Twitter) at @FultonW_.

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